Bash - working with If statement:

In bash if statement starts with 'if' and ends with 'fi'.syntax look like below

if [Boolean condition];then

statement(s) to be executed on if condition evaluate to be true

else

statement(s) to be executed on if condition evaluate to be false

fi;

look into below code spinet,it has three section

1) this section shows only if statement without no else couterpart

2) second section contain if with else

3)in third we are declaring two variables T1 & T2 and initializing it with some values.

T1="i";

T2="we";

this

The if condition is based on values of created variable bash $ stand for value of something so when we say

echo "$T1";

first the value of T1 variable is found then echoed please note that wrt $ following statement are not same

echo "$T1";#this will print value of variable T1

                          vs

echo $"T1";#this will always print T1

anything return after # on that line is considered as comment
e,g.

#this is a comment

"echo -e" appears in below code as we have newline character that need to be interpretation.

for more details on various style of "echo" construct, run command "man echo"

[CODE]

#!/bin/bash

#simple if without else

if [ 1 = 1 ]; then

echo -e "\n1) Simple IF :1=1 is a universal truth evaluate to be true once & for all\n";

fi;

#simple if with else

if [ 1 = 1 ]; then

echo -e "2) Simple IF & ELSE : 1=1 is a universal truth evaluate to be true once for all\n";

else

echo -e "2) Simple IF & ELSE :unfortunately this line will never ever execute\n";

fi;

#variable declaration & if

T1="is";

T2="we";

echo "$T1";

if [ "$T1" = "$T2" ]; then

echo -e "3) my i is my we\n";

else

echo -e "4) my i is not my we\n";

fi;